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fsolve for matrix input
Hi everyone, I'm trying to solve a system of nonlinear equations using fsolve where the unknows are a matrix of size 2xS (S c...
fast 6 Jahre vor | 0 Antworten | 0
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How to build a cuda kernel from MATLAB m files?
I have a set of ODE's that I'm solving with the Runge-Kutta method in MATLAB. In each iteration I implement around 30 calls to f...
mehr als 8 Jahre vor | 0 Antworten | 0
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accessing data while working on gpu
Hi everyone I am going to use a gpu to speed the fft2 command during an iteration which includes around 10,000,000 times call...
mehr als 8 Jahre vor | 0 Antworten | 0
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fft-based differentiation on a non-periodic time span
Hi everybody I'm puzzled with a basic property of the Fourier transform. We all know that if the fourier transform of f(t) is...
etwa 9 Jahre vor | 0 Antworten | 0
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Multiplication in time domain using 2D circular convolution in frequency domain
Hi everyone I'm trying to do a time domain multiplication using 2D circular convolution in frequency domain. Actually I know ...
etwa 9 Jahre vor | 1 Antwort | 0
1
AntwortInterpolation using average of pixels
Hi I had the same problem of too large measurement size of 2048*2048 and I wanted to have 1024*1024, 512*512 and so on. I jus...
mehr als 9 Jahre vor | 0
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How can I make fft2 parallel?
Hi guys I got a code consisting of 3 loops and packed with fft2 command. Since it is not possible to make the code itself par...
mehr als 9 Jahre vor | 1 Antwort | 0
1
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a saw-shaped IFFT in matlab
I have a problem with the inverse Fourier transform of a function that is supposed to be smooth, but in practice, it becomes saw...
mehr als 10 Jahre vor | 1 Antwort | 0
1
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How to implement ifft?
Dear all I have been having a big problem understanding the concept of numerical ifft. Consider a function in spatial domain ...
mehr als 10 Jahre vor | 0 Antworten | 0
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how to evaluate a convolution integral by fast fourier transform
I need to evaluate a convolution integral by fft. Therefore, I have read somewhere in a paper to first zero-pad two multiplying ...
mehr als 10 Jahre vor | 1 Antwort | 0
