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ajay kumar


Aktiv seit 2013

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NEED HELP.... i have two modules aes and rc4 nencryptions. HOW CAN I MEASURE TIME TAKEN BY THEM TO COMPLLE AES DATA AND RC4 DAT.
HOW MUCH TIME TAKEN BY AES TO ENCRYPT AND DECRYPT? HOW MUCH TIME TAKEN BY RC4 TO ENCRYPT AND DECRYPT? WHAT COMMANDS I ...

mehr als 10 Jahre vor | 0 Antworten | 0

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need advice on using RESHAPE AND IMRESIZE
HI, 1* IF WE TAKE ONE IMAGE a=imread('moon.tif'); 2* IMRESIZE IT AS M*N MINE WAS128*...

fast 11 Jahre vor | 2 Antworten | 0

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errors in using RESHAPE FUNCTION......PLEASE HELP ME.
HI, WHAT I HAVE DONE IS. 1.RED ONE IMAGE STOREDF AS IMAZE NAME=A; 2.RESIZE IT INTO 128*128 MANNER 3.I WANT THESE PIXEL EL...

fast 11 Jahre vor | 1 Antwort | 0

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ERRORS IN MY CODE PLESE CORRECT ME.
I HAVE ERRORS IN MY CODE ..PLESE CORRECT THEM.... my code is attached. errors are Undefined function 'randsr...

etwa 11 Jahre vor | 1 Antwort | 0

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how to convert 24 bit depth images into 8 bit depth and 16 bit depth images.
i have 24 bit depth images. but i need them in 8 bit depth and 16 bit depth format. can any one sugest how to convert them. ...

etwa 11 Jahre vor | 2 Antworten | 0

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i have 1000*1000 pixel image.how can i convert it into m*n(400*300) pixel image.
i have 1000*1000 pixel image.how can i convert it into m*n(400*300) pixel image.

etwa 11 Jahre vor | 1 Antwort | 0

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i require code for watermark embeding and extraction of watermark in encrypted domain and spatial domain
i require code for watermark embeding and extraction of watermark in encrypted domain and spatial domain

etwa 11 Jahre vor | 1 Antwort | 0

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can i discuss about image encryption topic or not?
in this matlab answer community,can't i discuss about image encryption?

etwa 11 Jahre vor | 1 Antwort | 0

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can i get code for picture encryption and decryption
i require code for image encryption /decryption. can any one help me....

etwa 11 Jahre vor | 0 Antworten | 0

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can i get code for image encryption/decryption
i require code for picture encryption/decryption process. can any one provide.........

etwa 11 Jahre vor | 3 Antworten | 0

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