hisham mohammed

Last seen: mehr als 2 Jahre vor | Aktiv seit 2022

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Welcome I have a CF equation that performs a three-dimensional summation process and gives a two-dimensional result I did this process using (For Loops) in MATLAB. I want to c
clc xm(:,:,1)= [1 2 3 4;2 3 4 5;3 4 5 6;4 5 6 7 ] xm(:,:,2)= [2 3 4 5;3 4 5 6;4 5 6 7;5 6 7 8] tic [cf] =coherence_factor(...

fast 3 Jahre vor | 1 Antwort | 0

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Frage

Hello, how can I calculate the row and column by inserting a 3D matrix using this equation,, so that the input 3D matrix and output 2D matrix
clc clear all close all xm= [5 5 5 5;5 -4 -3 -2;5 -1 0 1;5 2 3 4] n=length(xm); [cf] =coherence_factor(xm,n) function ...

fast 3 Jahre vor | 1 Antwort | 0

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Frage

Hello, how can I calculate the row and column by inserting a 3D matrix using this equation
clc clear all close all xm= [5 5 5 5;5 -4 -3 -2;5 -1 0 1;5 2 3 4] n=length(xm); [cf] =coherence_factor(xm,n) function ...

fast 3 Jahre vor | 0 Antworten | 0

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Frage

Hello, how can I do a (for loop) for this equation to find more than one value of the CF ? Specifically, I mean more than one value for (xm)
function [CF]= Coherence_Factor(xm,N); CF = ((abs (sum(xm))).^2) / (N* sum(abs(xm.^2))) end %Function call window xm= [-1:...

fast 3 Jahre vor | 2 Antworten | 0

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Frage

Hello, how can I do a (loop) for this equation to find more than one value of the CF ? Specifically, I mean more than one value for (xm)
function [CF]= Coherence_Factor(xm,N); CF = ((abs (sum(xm))).^2) / (N* sum(abs(xm.^2))) end

fast 3 Jahre vor | 1 Antwort | 0

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Frage

Hello, I would like to convert this mathematical equation into MATLAB with function code.

etwa 3 Jahre vor | 0 Antworten | 0

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Frage

Hello, I would like to convert this mathematical equation into MATLAB code.

etwa 3 Jahre vor | 1 Antwort | 0

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