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Teshome Kumsa


Last seen: fast 2 Jahre vor Aktiv seit 2021

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Plots in a loop
Assume I had a matrix of dimension nX20. I want to plot each column using a loop, but there is some problem in giving a title fo...

fast 2 Jahre vor | 1 Antwort | 0

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I want to create cell arrays containing all zero elements in them.
Dear all, I am dealing with some stress transformation. I want to create a cell array C = cell (1,20). In each cell array, I wa...

fast 2 Jahre vor | 1 Antwort | 0

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Filling the matrix entries
I have a matrix to deal with. A=[1 2 3 4 5 6 7;4 6 7 4 5 8 7; 6 7 8 9 3 5 6]; for i=1:3 A(i,i)=0; end In the above sim...

fast 2 Jahre vor | 1 Antwort | 0

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Hold on with subplot in a loop
Hello, Hold on, command is messing up my life. I was trying to plot figures using a loop. I want the first two loops in one sub...

fast 2 Jahre vor | 1 Antwort | 0

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Error message "Index exceeds the number of array elements. Index must not exceed 3"
I have a vector of length 16384 in a cell. In some parts of my code I need up to half length, but I got an error message "Index ...

fast 2 Jahre vor | 1 Antwort | 0

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loop with subplot in MATLAB
I have data sets in the cell. Then I want to deal with those data sets. I have included my sample code here below. I want to plo...

fast 2 Jahre vor | 1 Antwort | 0

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Exponential of very large number
Hello all! I was trying to calculate exponental of some vectors. Actually my vector has very big entries(each entries are Stress...

mehr als 2 Jahre vor | 1 Antwort | 0

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Hello all! I have some ambiguity with MATLAB. I saved my matrix as A(:,:,1) in workspace. Now I want to access column or some entries of my big matrix on command window.
I have the following loop. for i=1:4 A(:,:,i)=i*ones(4,4); end Now I want second rows of A(:,:,i) i.e second row of A(:,:...

mehr als 2 Jahre vor | 2 Antworten | 0

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