The aim is to remove the elements before and after NaN occurrences inside a vector.

For example:

 x = [6 10 5 8 9 NaN 23 10 7 3 21 43 NaN 4 6 7 8]

The output y will be:

 y = [6 10 5 8 10 7 3 21 6 7 8]

If NaNs occur at the beginning or end then first two or last two values are removed.

 x=[NaN 1 2 3]  yields [2 3]

NaN values will exist in every case. No case is an empty set.

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Last Solution submitted on Mar 05, 2026

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Pauli Huusari Riccardo G. Shahriar Kabir Lorenzo

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