Problem 60576. Perimeter of a Koch snowflake
A Koch snowflake is an iteratively generated (fractal) shape built out of successively smaller equilateral triangles by following these steps:
- Draw an equilateral triangle. (n = 0)
- Divide the line segment into three segments of equal length.
- Draw an equilateral triangle that has the middle segment from step 2 as its base and points outward.
- remove the line segment that is the base of the triangle from step 3. (n = 1)
- Repeat steps 2 - 4. (n = 2,3,...)
In the limit of this shape has an infinite perimeter and a finite area. For , this perimeter is calculable. Calculate both of these values for any input value of n and any starting triangle edge length, s.
[A1,P1] = KochSnowflake(n,s)
Solution Stats
Problem Comments
-
1 Comment
Christian Schröder
on 12 Jul 2024
Nice problem!
Solution Comments
Show commentsProblem Recent Solvers7
Suggested Problems
-
How to find the position of an element in a vector without using the find function
2728 Solvers
-
3281 Solvers
-
361 Solvers
-
Get the length of a given vector
10947 Solvers
-
Permute diagonal and antidiagonal
446 Solvers
Problem Tags
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!