Problem 487. Find perfect placement of non-rotating dominoes (easier)
Given a list of ordered pairs, find the order they should be placed in a line, such that the sum of the absolute values of the differences is zero.
list = [1 2
        4 3
        2 4
order = [1 3 2]
yields: [1 2][2 4][4 3]
    or: abs(2-2) + abs(4-4)
    or:        0 + 0
    or: 0
There is a unique solution to this problem where the final score is zero.
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Problem Comments
- 
		3 Comments
		Manish Joshi
    	on 18 May 2015
	
	
  	Interesting...
		Roche de Guzman
    	on 18 Oct 2016
	
	
  	awesome problem!
		Tran Tran
    	on 24 Jul 2022
	
	
  	Perms() go bruhhh
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