Problem 44068. The number of trailing zero digit of a factorial

vpa(factorial(27)) = 10888869450418351940239884288

...
no trailing zeros
factorial(27) = 1.088886945041835e+28
...

vpa(factorial(27)) - 1.088886945041835e+28 - 2.199023255552000e+12 = 0

I don't get it.
if vpa(factorial) = 10888869450418351940239884288
then there are no trailing zeros...

vpa(factorial(11)) = 39916800
two trailing, like in your problem statement...

am I crazy?

Highphi, any factorial equal to or greater than 5! has to have trailing zeros because it will have one or more pairs of 2 and 5 in its factors. I think factorial(vpa(27)) will give the correct value.