Suppose f and g are function_handles, try to define f+g,f-g,f*g and f/g.

e.g. 
   if   f = @(x)x and g = @(x)x+1
   then
        f+g = @(x)2*x+1
        f-g = @(x)-1
        f*g = @(x)x*(x+1)
        f/g = @(x)x/(x+1)
Solve

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Last Solution submitted on Dec 10, 2025

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Mehdi Dehghan Caitlin 晨哲 ROBERTO

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