Tim created another superb solution. The highlights are an elegant center of square's determination using ndgrid. The crux of his method is a convolution for each square not using "same" with an interesting centroid kernel. The comparison between all square convolutions for all rotations utilizes a concise norm metric function. The method should work on non-binary images. The best six matches from the 180x180 upper triangle error array are handily converted into the output format. Thank You Tim for this elegant solution.
Is my wife right?
Find the largest value in the 3D matrix
intersection of matrices
Set a diagonal
Adding and Subtracting UINT variables
Molecule Atomic Wt (CHONS) Molecules
Genome Sequence 003: DNA Sequence with random positioned segments
Alias abs to asb
GJam March 2016 IOW: Password Single
Find the treasures in MATLAB Central and discover how the community can help you!
Choose a web site to get translated content where available and see local events and offers. Based on your location, we recommend that you select: .
You can also select a web site from the following list:
Select the China site (in Chinese or English) for best site performance. Other MathWorks country sites are not optimized for visits from your location.
Contact your local office