Problem 365. Numbers with prime factors 2, 3 and 5.
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3 Comments
Michael
on 25 Mar 2020
The problem statement should specify that i, j, and k are non-negative integers or the number of answers becomes infinite.
Michael
on 25 Mar 2020
Also, why is 1 not included in all of the answers. 2^0*3^0*5^0 = 1
Rafael S.T. Vieira
on 16 Jul 2020
This problem requests the set of hamming numbers without the number one for some reason. https://rosettacode.org/wiki/Hamming_numbers
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