According to Google translate, "driemaal is scheepsrecht" means "third time lucky" in Dutch.
I was wondering who would try this one, and how many iterations it would take. :-)
You can also try this solution style with another Cody problem.
Decode a simplified barcode
Remove white space from the string
Replace multiples of 5 with NaN
Sum the numbers on the main diagonal
Create incremental spiral WITHOUT USING EVAL or FEVAL
Add a row of zeros on top of a matrix
Operate on matrices of unequal, yet similar, size
A SUBSREF variant that accepts the 'end'-operator.
Make a KITT-scanner on the command line
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