How to plot using a loop on the same axis
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
Tebogo Makobe
am 14 Aug. 2021
Kommentiert: Tebogo Makobe
am 14 Aug. 2021
Would like to plot without having to hard code every single line up to 20+ customers(20 x 1 structure). Had an attempt at a for loop, the error message states that the number of element on the right are not same as on the left
%Graphical representation
t = 0:0.1:310; % Time vector for plots (m)
[position1,speed1,Duration1] = calcFallForPerson(customer(1),4200,0.1,1500);
[position2,speed2,Duration2] = calcFallForPerson(customer(2),4200,0.1,1500);
[position3,speed3,Duration3] = calcFallForPerson(customer(3),4200,0.1,1500);
[position4,speed4,Duration4] = calcFallForPerson(customer(4),4200,0.1,1500);
figure(1)
plot(t,position1,t,position2,t,position3,t,position4)
title('Posiion')
xlabel('Time(s)')
ylabel('Postion(m)')
xlim([0 320])
ylim([0 4500])
figure(2)
plot(t,speed1,t,speed2,t,speed3,t,speed4)
title('Velocity')
xlabel('Time(s)')
ylabel('Velocity(m/s)')
xlim([0 320])
ylim([0.0 60.0])
xlim([0 320])
ylim([0.0 60.0])
0 Kommentare
Akzeptierte Antwort
Wan Ji
am 14 Aug. 2021
Is the time array t the same size as position1,speed1 for each loop with different customers? If so, then following loop will help you!
t = 0:0.1:310; % Time vector for plots (m)
number_of_customer = 20; % change as you want
[position,speed,Duration] = arrayfun(@(i)acalcFallForPerson(customer(i),4200,0.1,1500),...
1:1:number_of_customer, 'uniform', false);
figure(1)
arrayfun(@(i)plot(t,position{i}),1:1:number_of_customer);
title('Posiion')
xlabel('Time(s)')
ylabel('Postion(m)')
xlim([0 320])
ylim([0 4500])
figure(2)
arrayfun(@(i)plot(t,speed{i}),1:1:number_of_customer);
title('Velocity')
xlabel('Time(s)')
ylabel('Velocity(m/s)')
xlim([0 320])
ylim([0.0 60.0])
xlim([0 320])
ylim([0.0 60.0])
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Line Plots finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!