Loop to populate a 12 by 12 matrix

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DARLINGTON ETAJE
DARLINGTON ETAJE am 24 Jun. 2021
Kommentiert: DARLINGTON ETAJE am 24 Jun. 2021
Hello Guys,
I am tryling to form a 12 by 12 matrix for 11 elements. I am getting some errors. Take a look at my code below: it looks perfect to me but it is not working
SC1=rand(11,1);% Test Data
SC2=rand(11,1);
SC3=rand(11,1);
SC4=rand(11,1);
SC5=rand(11,1);
SC6=rand(11,1);
SC7=rand(11,1);
SC8=rand(11,1);
n=size(SC8,1);
K1=zeros(12,1);
K2=zeros(12,1);
K3=zeros(12,1);
K4=zeros(12,1);
K5=zeros(12,1);
K6=zeros(12,1);
K7=zeros(12,1);
K8=zeros(12,1);
K9=zeros(12,1);
K10=zeros(12,1);
K11=zeros(12,1);
K12=zeros(12,1);
K=zeros(12,12);
for i=1:n
K1(i)=[SC1(i);0;0;0;0;0;-SC1(i);0;0;0;0;0];
K2(i)=[0;SC6(i);0;0;0;SC2(i);0;-SC6(i);0;0;0;SC2(i)];
K3(i)=[0;0;SC7(i);0;-SC3(i);0;0;0;-SC7(i);0;-SC3(i);0];
K4(i)=[0;0;0;SC4(i);0;0;0;0;0;-SC4(i);0;0];
K5(i)=[0;0;-SC3(i);0;(2*SC5(i));0;0;0;SC3(i);0;SC5(i);0];
K6(i)=[0;SC2(i);0;0;0;(2*SC8(i));0;-SC2(i);0;0;0;SC8(i)];
K7(i)=-K1;
K8(i)=-K2;
K9(i)=-K3;
K10(i)=-K4;
K11(i)=[0;0;-SC3(i);0;SC5(i);0;0;0;SC3(i);0;(2*SC5(i));0];
K12(i)=[0;SC2(i);0;0;0;SC8(i);0;SC2(i);0;0;0;(2*SC8(i))];
K(i)=[K1(i) K2(i) K3(i) K4(i) K5(i) K6(i) K7(i) K8(i) K9(i) K10(i) K11(i) K12(i)];
end
  1 Kommentar
DARLINGTON ETAJE
DARLINGTON ETAJE am 24 Jun. 2021
Thank you so much Walter. It worked. You are an excellent person. The only challenge is that working with the code in struct is different than in a double.

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Walter Roberson
Walter Roberson am 24 Jun. 2021
SC1=rand(11,1);% Test Data
SC2=rand(11,1);
SC3=rand(11,1);
SC4=rand(11,1);
SC5=rand(11,1);
SC6=rand(11,1);
SC7=rand(11,1);
SC8=rand(11,1);
n=size(SC8,1);
K1 = repmat({zeros(12,1)},n,1);
K2 = repmat({zeros(12,1)},n,1);
K3 = repmat({zeros(12,1)},n,1);
K4 = repmat({zeros(12,1)},n,1);
K5 = repmat({zeros(12,1)},n,1);
K6 = repmat({zeros(12,1)},n,1);
K7 = repmat({zeros(12,1)},n,1);
K8 = repmat({zeros(12,1)},n,1);
K9 = repmat({zeros(12,1)},n,1);
K10 = repmat({zeros(12,1)},n,1);
K11 = repmat({zeros(12,1)},n,1);
K12 = repmat({zeros(12,1)},n,1);
K = repmat({zeros(12,1)},n,1);
for i=1:n
K1{i} = [SC1(i);0;0;0;0;0;-SC1(i);0;0;0;0;0];
K2{i} = [0;SC6(i);0;0;0;SC2(i);0;-SC6(i);0;0;0;SC2(i)];
K3{i} = [0;0;SC7(i);0;-SC3(i);0;0;0;-SC7(i);0;-SC3(i);0];
K4{i} = [0;0;0;SC4(i);0;0;0;0;0;-SC4(i);0;0];
K5{i} = [0;0;-SC3(i);0;(2*SC5(i));0;0;0;SC3(i);0;SC5(i);0];
K6{i} = [0;SC2(i);0;0;0;(2*SC8(i));0;-SC2(i);0;0;0;SC8(i)];
K7{i} = -K1{i};
K8{i} = -K2{i};
K9{i} = -K3{i};
K10{i} = -K4{i};
K11{i} = [0;0;-SC3(i);0;SC5(i);0;0;0;SC3(i);0;(2*SC5(i));0];
K12{i} = [0;SC2(i);0;0;0;SC8(i);0;SC2(i);0;0;0;(2*SC8(i))];
K{i} = [K1(i); K2(i); K3(i); K4(i); K5(i); K6(i); K7(i); K8(i); K9(i); K10(i); K11(i); K12(i)];
end
K
K = 11×1 cell array
{12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell}
K{1}
ans = 12×1 cell array
{12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double}
K{1}{1}
ans = 12×1
0.3563 0 0 0 0 0 -0.3563 0 0 0

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