# why coding this function returns un exact numerical results?

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Cantor Set am 22 Jun. 2021
Kommentiert: Walter Roberson am 23 Jun. 2021
Ackley's Function (a=20,b=0.2) d=2.
function [ y ] = objfun14 (phen )
d=size(phen,2);
v=cos(2*pi*phen); x=(1/d)* sum(v,2);
t=-20*exp(-0.2*sqrt((1/d)*sum(phen.^2,2))) - exp( x ) +20+exp(1);
y=sum(t,2);
end
%when phen=[0 0] the output should be t=0 however excuting the code gives t=8.8818e-16
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Scott MacKenzie am 22 Jun. 2021
t=8.8818e-16 is pretty close to zero. You are dealing with floating point arithmetic, that's why the result is not exactly what you expect. See Floating-Point Numbers for further details.

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### Antworten (1)

Kishan Dhakan am 23 Jun. 2021
Try using 'format long', which shows 15 decimal places. If it still doesn't work, then your value is probably smaller than what many call 'machine epsilon' and hence is getting rounded to zero.
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Walter Roberson am 23 Jun. 2021
The other way around, the function is returning -4*eps when the user expects 0

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