A problem while splitting a text input with regexp
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
I have a text file with the input as
sammy yo yo
yoyo with you
Samyukta
and I tried the following code to put each word into an element of an array.
fid = fopen('test4.txt');
table = fscanf(fid,'%c');
table2 = regexp(table,'\n','split');
this means that when I refer to table2{1}, it returns 'sammy yo yo' then I split every line individually with strsplit and ' ' (whitespace) as the delimiter. Therefore, when I refer to table2{1}{2} , it returns 'ýo'. But, the last word of every line has more number of letters than appears i.e. size(table2{1}{2},2) = 3 rather than 2. But when I strcmp it with '\n' and ' ' or any other thing, it returns 0. So now I don't know what to do.
2 Kommentare
Walter Roberson
am 15 Aug. 2013
What shows up for
table2{1}{2}(end) + 0
I suspect you will find it is 13 (carriage return)
Akzeptierte Antwort
Cedric
am 15 Aug. 2013
>> fprintf('%d,', table) ; fprintf('\n') ;
115,97,109,109,121,32,121,111,32,121,111,13,10,121,111,121,111,32,119,105,
116,104,32,121,111,117,13,10,83,97,109,121,117,107,116,97,13,10,
As you can see, at the end of each line, there are 13 (carriage return: '\r') and 10 (new line: '\n').
If you just want to split words, why don't you split using REGEXP only with a pattern which matches whitespaces? For example:
>> buffer = fileread('test4.txt') ;
>> words = regexp(buffer, '\s+', 'split')
words =
'sammy' 'yo' 'yo' 'yoyo' 'with' 'you' 'Samyukta' ''
with this, you would just have to delete the last cell when empty (which happens when your file ends with '\r\n'), and you would be done.
2 Kommentare
Walter Roberson
am 15 Aug. 2013
Only if the file was created with an older MS Windows editor. More modern MS Windows editors only put in \n (newline) without \r (carriage return). Linux and OS-X have never used \r . (MacOS before OS-X might have used \r )
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Characters and Strings finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!