Find which row of 3d matrix matches an array along the third dimension. For ex:
I want to find [1 0 0] along 3rd dimension of Zb, so here Zb(4,1,:) , Zb(5,4,:) and some others match [1, 0, 0]. How to know if the match occurs (for any random value of 3rd dimension of matrix) and if so, what are the row, column indices? Also, can this be done without for loop?

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Jonas
Jonas am 19 Mai 2021

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you can use e.g.
a(:,:,1)=ones(2);
a(:,:,2)=2*ones(2);
a(:,:,3)=[1 3; 3 1];
pattern(1,1,:)=1:3;
whereToFind=all(a==pattern,3)

2 Kommentare

Shilpi Mishra
Shilpi Mishra am 20 Mai 2021
Thanks a lot, to know positions of 1 in the whereToFind, is there a direct way without loop to get list of indices as [4,1], [3,2] and so on?
Jonas
Jonas am 20 Mai 2021
Bearbeitet: Jonas am 20 Mai 2021
yes, use
[row,col]= find(whereToFind)
if you want the pairwise indices then [row col] will give you all pairs

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