Linear Label on Logarithmic Plot
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Hello!
I have an "example" regression loglog graph to show someone. The Y axis is not very large, but is less than 1, so it shows up as log rather than linear.
Is there a way to do this cleanly? Here's the code:
% reggie
rng('shuffle');
Intercept = 1000;
Slope = -1.6;
dist = 150:50:300;
vib = Intercept*(dist.^Slope);
minx = 50;
maxx = 400;
figure
loglog(dist,vib,'o','MarkerFaceColor','r')
xlim([minx maxx])
ylim([0.05 1])
hold on
grid on
grid minor
loglog([minx maxx],[Intercept*(minx^Slope) Intercept*(maxx^Slope)],'--');
xlabel('Distance (ft)');
ylabel('Vibration (in/s)');
title('Regression Example');
for n = 1:length(dist)
scatterling = 0.3 * vib(n);
median_value = vib(n);
new_values = scatterling.*randn(6,1)+median_value;
loglog(dist(n),new_values,'diamond','LineStyle','none');
end
newdist = 100;
reduction_factor = 0.65;
newvib = (reduction_factor * Intercept) *(newdist.^Slope);
loglog(newdist,newvib,'o','MarkerFaceColor','b');
scatterling = 0.4 * newvib;
median_value = newvib;
new_values = scatterling.*randn(6,1)+median_value;
loglog(newdist,new_values,'diamond','LineStyle','none','MarkerFaceColor','g');
Thanks!
Doug
2 Kommentare
Walter Roberson
am 13 Mai 2021
It is not clear what you are asking for??
You do loglog plots. If you do not want to reprogram that to linear, you could
set(gca, 'YScale', 'linear')
Douglas Anderson
am 14 Mai 2021
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