How do you get the value for any point on the response plane?

Branin function

I used the Latin Hypercube design.

x1 = [4.158236141 6.153599506 -4.535940798 7.598349019 1.546377884 -1.345068203 9.996482015 -0.173832303 -4.963945249 7.601915038 6.858088405 6.026235301 3.704288407 3.26674903 3.077538527 3.32612663 3.171101989 9.937861391 9.863387191 -4.925131257]

x2 = [2.015908909 12.95555116 11.95848613 6.917196588 9.949209037 2.568895989 0.600398657 14.98330222 6.845564827 3.014910507 0.181581313 2.019090607 2.012738027 2.016006495 0 5.08610712 2.193143018 10.52404152 14.64506378 0.388181645]

v = [5.107328283 160.1220683 23.67014797 43.25143692 47.46188065 45.85372988 7.680346552 95.19501237 117.2067804 15.11163604 19.01778002 20.13095512 1.896743409 0.499697271 5.825451311 9.267063133 0.405543669 59.12461059 139.9629599 287.0573273]

x1:[-5 10], x2:[0 15]

x1 = -3.4 , x2 = 1.6 At this time, I want to know the value.

Please let me know.

Answer 1

[KSSV]

x1 = [4.158236141 6.153599506 -4.535940798 7.598349019 1.546377884 -1.345068203 9.996482015 -0.173832303 -4.963945249 7.601915038 6.858088405 6.026235301 3.704288407 3.26674903 3.077538527 3.32612663 3.171101989 9.937861391 9.863387191 -4.925131257];
x2 = [2.015908909 12.95555116 11.95848613 6.917196588 9.949209037 2.568895989 0.600398657 14.98330222 6.845564827 3.014910507 0.181581313 2.019090607 2.012738027 2.016006495 0 5.08610712 2.193143018 10.52404152 14.64506378 0.388181645];
v = [5.107328283 160.1220683 23.67014797 43.25143692 47.46188065 45.85372988 7.680346552 95.19501237 117.2067804 15.11163604 19.01778002 20.13095512 1.896743409 0.499697271 5.825451311 9.267063133 0.405543669 59.12461059 139.9629599 287.0573273];

F = scatteredInterpolant(x1',x2',v') ;
xi = -3.4 ;
yi = 1.6 ;
vi = F(xi,yi)

[민제 강]

Thank you for your answer.

Can I use kriging to get date? Not scatteredInterpolant.