regular expression to replace ~ in code

6 Ansichten (letzte 30 Tage)
Robert Alvarez
Robert Alvarez am 11 Jul. 2013
Edit: wrote new function StripTildes.m (see below) that works with all cases including output list on multiple lines
Edit: Modified the StripTildes function to use Daniel's regular expression from FEX function. This still does not work with modified TestFunction that uses a line continuation in the output argument list.
My version of Matlab does not support the use of ~ in an output argument list so it is giving syntax errors when I try to use some downloaded code.
My regular expressions are extremely rusty so I would appreciate a regular expression to use with regexprep to replace the ~ in an output argument enclosed in brackets but not replace ~= and other uses of the symbol.
responding to Azzi's comment: I would like to replace ~ with a regular variable name like 'dummy' so it will not cause a syntax error. The rest of the code should then work OK so long as there is no collision with an existing variable name.
My idea is to write a Matlab function to scan the downloaded code file, replace the ~'s, and then write the output to another file.
My editor 'Editpad' allows regular expression search and replace so I can also use the regular expression with it but for definiteness please stick with regexprep and I will take it from there.
Question: I am no clear the allowable syntax. Are only spaces between output arguments allowed such as?
[~ ~ y3 ] = NewFunction(foo);
TIA.
I created a function to implement the filtering and a test function as follows:
1. the filtering function
function StripTildes(filename)
% replace tildes in output parameter lists with 'the_dummy'
% in Matlab file filename
% outputs new file named filename_notilde.m to same directory as original file
pattern='~(?=[^\]\[='']*\][\s(\.\.\.)]*=[^=])'; % regular expression to find tildes
fid = fopen(filename); % open for read only
assert( fid ~= -1);
% read all file into one long string (including line break chars) so regexprep can work across lines
filetext = [];
while 1
tline = fgets(fid);
if ~ischar(tline), break, end % quit at end of file
filetext = [filetext tline];
end
fclose(fid);
filetext = regexprep(filetext,pattern,'the_dummy');
% output the file
[path,name,ext] = fileparts(filename);
out_name = [path filesep name '_notilde' ext];
fidout = fopen(out_name,'w');
assert( fid ~= -1);
fwrite(fidout,filetext);
fclose(fidout);
2. the function to test
function TestFunction
if 1 ~= 0
[~,~,y] = LocalFunction;
elseif ~(true) or ~exist(foo,'dir')
[~ ~ y ] = LocalFunction;
end
tf = [~true, 1~=0, ...
];
[~,~, ...
y] = LocalFunction;
function [y1,y2,y3] = LocalFunction
y1 = 0;
y2 = 0;
y3 = 0
p.s. I cannot afford to upgrade my Matlab version so please do not suggest it as a solution
  6 Kommentare
per isakson
per isakson am 11 Jul. 2013
Bearbeitet: per isakson am 11 Jul. 2013
I modified the expression below to handle [~,~,y] and [~,a,~]
Robert Alvarez
Robert Alvarez am 11 Jul. 2013
I fixed a bug in StripTildes function and modified TestFunction.

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

per isakson
per isakson am 11 Jul. 2013
Bearbeitet: per isakson am 11 Jul. 2013
regexprep( '[ a, ~, b ]', '(?<=\[.+?,[ ]*)\~(?=.+?])', 'dummy' )
returns
[ a, dummy, b ]
Firstly, backup all your files
and make more tests
.
Always check the FEX. See replaceTildes
.
Bugfix:
str = '[~,~,y] = LocalFunction;';
regexprep( str, '(?<=\[(.+?,)|([ ]*)[ ]*)\~(?=.+?])', 'dummy' )
returns
ans =
[dummy,dummy,y] = LocalFunction;
.
and another bugfix
str = '[~,a,~] = LocalFunction;';
regexprep( str, '(?<=\[(.+?,)|([ ]*)[ ]*)\~(?=.*?])', 'dummy' )
returns
ans =
[dummy,a,dummy] = LocalFunction;
and more test needed
  7 Kommentare
per isakson
per isakson am 11 Jul. 2013
Bearbeitet: per isakson am 11 Jul. 2013
Try this
reg = '(?<=\[(.+?,)|([ ]*)[ ]*)\~(?=.*?][ ]*(=|(\.\.\.)))';
str = '[~,a,~] = LocalFunction;';
regexprep( str, reg, 'dummy' )
str = 'tf = [~true, 1~=0, ...';
regexprep( str, reg, 'dummy' )
str = '[~,a,~] ...';
regexprep( str, reg, 'dummy' )
The expression looks at one line. Thus, I give up on this one
[~,~, ...
y] = LocalFunction;
and after that we will face
[y,~, ...
~] = LocalFunction;
You could
  • concatenate the continuation lines
  • search&replace
  • restore the continuation lines
per isakson
per isakson am 11 Jul. 2013
FileLocator Lite is a free really good find_in_files_program. It will help you find the remaining cases, which you should edit interactively.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

Azzi Abdelmalek
Azzi Abdelmalek am 11 Jul. 2013
Bearbeitet: Azzi Abdelmalek am 11 Jul. 2013
str='one ~ two ~= three ~'
pattern='~(?!\S)'
regexprep(str,pattern,'dummy')
  2 Kommentare
Daniel Shub
Daniel Shub am 11 Jul. 2013
I think this will fail if the ~ is in a string. It is possibly better to also include [] since I think that is a requirement. I think counting opening/closing quoutes might be hard.
Azzi Abdelmalek
Azzi Abdelmalek am 11 Jul. 2013
Bearbeitet: Azzi Abdelmalek am 11 Jul. 2013
str=' z~d one ~ two ~= three ~'
pattern='~(?!\=)'
regexprep(str,pattern,'dummy')
%or
str=strrep(str,'~=','obma')
str=strrep(str,'~','dummy')
str=strrep(str,'obma','~=')

Melden Sie sich an, um zu kommentieren.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by