How can i perform an ADI method on 2d heat equation

14 Ansichten (letzte 30 Tage)
Mohammad Adeeb
Mohammad Adeeb am 24 Apr. 2021
Kommentiert: skerdi hymeraj am 8 Aug. 2022
im trying to slve this equation : 𝜕𝑇 𝜕𝑡 = 𝜕 2𝑇 𝜕𝑥 2 + 𝜕 2𝑇 𝜕𝑦 2
𝑇(𝑥, 𝑦, 0) = 0
𝑇(0, 𝑦,𝑡) = 0
𝑇(1, 𝑦,𝑡) = 0
𝑇(𝑥, 0,𝑡) = 0
(𝑥, 1,𝑡) = 100 sin 𝜋x
so for the first part which is in x direction i did the following :
close all;
clc;
dt = 0.001; %time step
dx = 0.1; %step in x direction
t = 0:dt:15; %time interval (changable due to your desighn)
x = 0:dx:1; %x-axis interval (changable due to your desighn)
lamda=dt/(2*dx^2);
a=(1+2*lamda)*ones(1,13);%define matrix A
A=diag(a); %make matrix a diagonal one
N = length(x)+2; %interval (changable due to your desighn)
for i=1:N-1
A(i+1,i)=-lamda;
A(i,i+1)=-lamda;
end
A(1,1)=1+2*lamda;
A(1,2)=-lamda;
A(13,12)=-lamda;
A(13,13)=1+2*lamda;
T=[]; %Dynamic size array
a2=lamda*ones(1,13);
A2=diag(a);
for j=1:N-3
A2(j+3,j)=(1-2*lamda);
A2(j,j+3)=(1-2*lamda);
end
T(:,:,:) = zeros(length(t),length(y)+2,length(x)+2); %define initial condition
Tstar=zeros(length(x),length(y));
Tall=zeros(length(x),length(y));
for k=2:length(t)
for j=2:length(x)-1
fx=(l-2*lamda)*T(:,j,k-1)+lamda*T(:,j-1,k-1)+lamda*T(:,j+1,k-1);
fx(1)=0;
fx(end)=0;
Tstar(j,:)=(A\fx)';
end
for i=2:length(y)-1
fy=(1-2*lamda)*Tstar(i,:)+lamda*Tstar(i-1,:)+lamda*Tstar(i+1,:);
fy(:,1)=0;
fy(:,end)=100*sin(pi*x(i));
end
Tall(:,j)=A\fy;
T(:,:,k)=Tall(:,:);
end
i've used imaginary node to solve the proplem , also i did the following analysis for the code :
what should i do?
  6 Kommentare

Melden Sie sich an, um zu kommentieren.

Antworten (0)

Kategorien

Mehr zu Mathematics and Optimization finden Sie in Help Center und File Exchange

Produkte


Version

R2020b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by