How to find the 4th special number among pentagonal and triangular numbers
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
Syed Hafiz
am 23 Apr. 2021
Bearbeitet: Chunru
am 23 Apr. 2021
A pentagonal number is defined by p(n) = (3n^2 – n)/2, where n is an integer starting from 1. Therefore, the first 12 pentagonal numbers are 1, 5, 12, 22, 35, 51, 70, 92, 117, 145, 176 and 210.
A triangular number is defined by t(n) = (n^2 + n)/2, where n is an integer starting from 1. Therefore, the first 12 triangular numbers are 1, 3, 6, 10, 15, 21, 28, 36, 45, 55, 66 and 78.
From the above example, the number 1 is considered 'special' because it is both a pentagonal (p=1) and a triangular number (t=1). Determine the 4th 'special' number (i.e. where p=t) that exists assuming the number 1 to the be first 'special' number.
0 Kommentare
Akzeptierte Antwort
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Data Type Conversion finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!