standard deviation of two elements of a 3d matrix

1 Ansicht (letzte 30 Tage)
William
William am 28 Jun. 2013
Greetings,
I have a 672 x 32 x 2800 matrix that I need to chop into a 672 x 2800 matrix but the rows need to be the standard deviation of the columns in the original 3d matrix. Here is what I am doing which is all wrong
new_col_data = zeros(672,2800);
new_col_data = [std(data, 0, 2),:]
I cannot figure this out. Can someone please tell me what is wrong?
Thank you

Akzeptierte Antwort

Shashank Prasanna
Shashank Prasanna am 28 Jun. 2013
Bearbeitet: Shashank Prasanna am 28 Jun. 2013
A = rand(672,32,2800); % Some random data:
B = std(A,[],2); % Compute the standard deviation
B = squeeze(B); % Squeeze it

Weitere Antworten (2)

Sean de Wolski
Sean de Wolski am 28 Jun. 2013
Sounds like you want to squeeze it!
squeeze(std(rand(60,30,45),0,2))

William
William am 28 Jun. 2013
I tried this:
>> new_col_data = squeeze(std(data,0,2),:);
Error using var (line 59)
First argument must be single or double.
Error in std (line 32)
Something went wrong. I do not have a single dimension in this matrix
  1 Kommentar
Sean de Wolski
Sean de Wolski am 28 Jun. 2013
Mine doesn't have a squeeze(blah,:). It's supposed to jsut be squeeze(blah)

Melden Sie sich an, um zu kommentieren.

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by