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I need to plot the same graphic of the image, but without any loop.

1 Ansicht (letzte 30 Tage)
Equation for f(x)
With loop i get this:
clear
clc
x = -5*pi:pi/100:5*pi;
k = 0;
y = zeros(size(x));
for k = 0:100
k = k + 1;
y = y + 2*( ( (-(-1).^k) / k ) .* sin(x*k) );
end
plot(x, y)
ylabel('f(X)')
xlabel('X')
grid
I tried to do this without loop but i getting errors.
clear
clc
x = -5*pi:pi/100:5*pi;
k = 0:1:100;
y = zeros(size(x));
% How to variable k ?
y = y + 2.*( ( (-(-1).^k) / k ) .* sin(x*k) );
sum(x)
sum(y)
plot(x,y)
  2 Kommentare
KALYAN ACHARJYA
KALYAN ACHARJYA am 18 Apr. 2021
I didnot find any output using your loop code also.
Luccas S.
Luccas S. am 18 Apr. 2021
Bearbeitet: Luccas S. am 18 Apr. 2021
I ended up not transcribing k = k +1 for publication, now i have changed.

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Akzeptierte Antwort

Walter Roberson
Walter Roberson am 18 Apr. 2021
x = -5*pi:pi/100:5*pi;
k = (1:1:100).'; %not 0!
y = sum(2.*( ( (-(-1).^k)./ k ) .* sin(x.*k) ));
plot(x,y)
  2 Kommentare
Luccas S.
Luccas S. am 18 Apr. 2021
Right, I am running the code in octave but it is not working in matlab. (Matrix dimensions must agree.)
Walter Roberson
Walter Roberson am 18 Apr. 2021
The above code works in R2016b and later.
Octave is not a programming language that I know.
xvals = -5*pi:pi/100:5*pi;
kvals = (1:1:100).'; %not 0!
[x, k] = meshgrid(xvals, kvals);
y = sum(2.*( ( (-(-1).^k)./ k ) .* sin(x.*k) ));
plot(x,y)

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