clc
clear
for a = [0.01 0.01 0.01 0.03 0.1 0.2 0.3 0.3 0.3 0.4 0.4 0.4 0.3 0.4 0.5 0.8 0.9 1 0.8 0.7 0.5 0.2 0.1 0.03];
b=a*5
end
How can I store new values of b for each iteration ?

1 Kommentar

Mischa Kim
Mischa Kim am 16 Apr. 2021
Hi Lauris, depends. What exactly are you trying to do?

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 Akzeptierte Antwort

David Hill
David Hill am 16 Apr. 2021

0 Stimmen

a = [0.01 0.01 0.01 0.03 0.1 0.2 0.3 0.3 0.3 0.4 0.4 0.4 0.3 0.4 0.5 0.8 0.9 1 0.8 0.7 0.5 0.2 0.1 0.03];
for k= 1:length(a)
b(k)=a(k)*5;%index into b
end
Better, just multiply, no loop needed.
b=5*a;

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