x=[3;5]
How to index in for loop
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rakesh kumar
am 2 Apr. 2021
Kommentiert: rakesh kumar
am 2 Apr. 2021
I have a an array
a=[4 9 7]
A Matrix
b= [5 7;4 2];
I want to have
c1=4*b c2=9*b; c3=7*b
. I want to use c1,c2"c3' later as d1=r-c1*x; d2=r-c2*x; Where r=[4;9]; x=[3 5]
Akzeptierte Antwort
David Hill
am 2 Apr. 2021
Bearbeitet: David Hill
am 2 Apr. 2021
for k=1:length(a)
c(:,:,k)=a(k)*b;%index instead of having different variables
d(:,:,k)=r-c(:,:,k)*x;
end
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