I can't plot square or rectangle correctly

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st0s
st0s am 27 Mär. 2021
Kommentiert: st0s am 27 Mär. 2021
x = input('enter x number:')
y = input('enter y number:')
z = input('enter widht:')
v = input('enter lenght:')
axes('NextPlot', 'add','XLim', [((-abs(x)-abs(z))+25), ((abs(x)+abs(z)+25))], 'YLim', [((-abs(y)-abs(v))+25), ((abs(y)+abs(v)+25))]);
for e = x:0.5:(abs(x)+abs(z))
plot(e, y, '*k')
pause(0.05)
end
for e = y:0.5:(abs(y)+abs(v))
plot(x,e, '*k')
pause(0.05)
end
for e = x:0.5:(abs(x)+abs(z))
plot(e,(abs(y)+abs(v)),'*k')
pause(0.05)
end
for e = y:0.5:(abs(y)+abs(v))
plot((abs(y)+abs(v)),e, '*k')
pause(0.05)
end
There is a issue with my last for-end loop. Last edge of rectangle doesn't fit correctly. Also I used 25 to see graph more clear. Can you check that. I feel like I did something wrong there too.

Akzeptierte Antwort

DGM
DGM am 27 Mär. 2021
Right off the bat, the xlim and ylim were way off in the weeds (at least for the parameters i chose). Try these changes:
% use meaningful descriptions
x = input('enter x offset: ')
y = input('enter y offset: ')
w = input('enter width: ')
h = input('enter height: ')
% filter these once instead of a bunch of times
w=abs(w);
h=abs(h);
clf
% here, i'm adding [h/2 w/2] margin around the box
% that's just something arbitrary i picked
axes('NextPlot', 'add','XLim', [x-w/2 x+w+w/2], 'YLim', [y-h/2 y+h+h/2]);
% why are you using abs(x) and abs(y) everywhere?
% that makes the size wrong if x or y is negative
% if x and y must be non-negative, filter them first, like with w and h
for e = x:0.5:(x+w)
plot(e, y, '*k')
pause(0.05)
end
for e = y:0.5:(y+h)
plot(x,e, '*k')
pause(0.05)
end
for e = x:0.5:(x+w)
plot(e,y+h,'*k')
pause(0.05)
end
for e = y:0.5:(y+h)
plot(y+h,e, '*k')
pause(0.05)
end
  3 Kommentare
DGM
DGM am 27 Mär. 2021
Bearbeitet: DGM am 27 Mär. 2021
Auugh my bad. I was using unity aspect ratio, so I didn't catch that.
for e = y:0.5:(y+h)
plot(x+w,e, '*k')
pause(0.05)
end
If there are some odd requirements for calculating the plot area, then you'll have to follow whatever you're being told to use for calculating xlim and ylim. That said, if [y x] is the location of one corner and [y+h x+w] is the other corner, then you don't need abs() in the loops anywhere.
st0s
st0s am 27 Mär. 2021
Thank you.

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