Converting an n x m matrix into a single array
3 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Ernest Modise - Kgamane
am 27 Mär. 2021
Beantwortet: DGM
am 27 Mär. 2021
I have the following
source = [8202, 8202, 8202, 8201, 8202, 8202, 8202, 8208];
I want to have an array containing the binary values of source but as a single array,
Array = ( de2bi(8202) de2bi(8202) .... de2bi(8206))
so that I can index the resultant bits of the eight entries one by one,
I am essentially trying to obtain a complete bit stream of source data in one array so that I can work with the individual bits
In this case I am expecting an array with 8 * ceil(log2(max(source)))
Kindly assist,
0 Kommentare
Akzeptierte Antwort
DGM
am 27 Mär. 2021
How about something like this?
source = [8202, 8202, 8202, 8201, 8202, 8202, 8202, 8208];
sbin=de2bi(source,'left-msb'); % pick which bit order you need
bitstream=reshape(sbin',[1 numel(sbin)]) % reshape into a vector
0 Kommentare
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Creating and Concatenating Matrices finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!