What is done in this line? f = f(arrayfun(@(x) x.name(1), f) ~= '.');

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Shaila parvin
Shaila parvin am 28 Mai 2013
clc
clear all
close all
dirpath = 'E:\4-1\image-thesis\implementation\shaila\';
f=dir(fullfile(dirpath,'*.jpg'));
f = f(arrayfun(@(x) x.name(1), f) ~= '.');
for i=1:length(f)
a=imread(strcat(dirpath,f(i).name));
if (ndims(a)==2 | (a(:,:,1)==a(:,:,2) & a(:,:,2)==a(:,:,3)))
%if (ndims(a)==2)
figure;imshow(a)
end
end
What is done in this line?
f = f(arrayfun(@(x) x.name(1), f) ~= '.');

Akzeptierte Antwort

Matt J
Matt J am 28 Mai 2013
Bearbeitet: Matt J am 28 Mai 2013
It takes file names obtained from DIR and throws away those that begin with '.'

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