Storing elements to a matrix

Hi everyone. This my code

clc
clear all
m=[ 1 2 3; 4 5 6; 7 8 9];
c=1;
for k=1:3;
  for f= 1:3;  
     
  m1(k,f)=(m(c+1,k)+m(c+2,f));
  
  end
  
end  
disp(m1);




for k=1:size(m,2)
  M(:,:,k)=m(1,k)+m1;
end
disp(M);

the output of this code is

 11    12    13
    12    13    14
    13    14    15


(:,:,1) =

    12    13    14
    13    14    15
    14    15    16


(:,:,2) =

    13    14    15
    14    15    16
    15    16    17


(:,:,3) =

    14    15    16
    15    16    17
    16    17    18

>> 

But I want to save all 27 values in a single matrix

how it can be done

[Sergey Kasyanov]

Hello, all 27 values are stored in 3-d dimensional matrix. If you want the 2-d matrix you should to describe what are you want in detail.

Answer 1

[ANKUR KUMAR]

3D data can be converted to 2D using reshape. You just need to reshape your matrix based on your requirements.

A1=reshape(M,3,[],1);

Above code yields to 3 X 9 matrix.

A2=reshape(M,[],3,1);

Above code yields to 9 X 3 matrix.

A3=reshape(M,9,[],1);

Above code yields to 9 X 3 matrix.

A4=reshape(M,[],9,1);

Above code yields to 3 X 9 matrix.

A1 and A4 are identical, and A2 and A3 are identical.

[Mohammad Juned]

Thanks a lot ANKUR KUMAR