to search fractal dimension
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Frisda Sianipar
am 13 Mär. 2021
Kommentiert: Walter Roberson
am 18 Mär. 2021
This is already the segmentation stage, and I want to find the fractal dimension but it has an error. Can someone help me?
image_folder = 'F:\kuliah\semester6\TA2\mencoba\output';
outfolder = 'F:\kuliah\semester6\TA2\mencoba\hasil';
if ~isdir(outfolder); mkdir(outfolder); end
files = dir(fullfile(image_folder, '*.jpg'));
%I presume it has the variable map in it
for iFiles = 1:numel(files)
thisfilename = fullfile(files(iFiles).folder,files(iFiles).name);
[~, basename, ext] = fileparts(image_folder);
citra = imread(thisfilename);
%change to grayscale
grayimg = rgb2gray(citra);
figure, fig2=imshow(grayimg);
%change to green channel
green_channel = citra(:,:,2);
figure, fig3=imshow(green_channel);
%change to CLAHE (Contrast Limited Adaptive Histogram Equalization)
CLAHE = adapthisteq(green_channel);
figure, fig4=imshow(CLAHE);
ER = edge(CLAHE, 'canny');
EG = edge(CLAHE, 'canny');
EB = edge(CLAHE, 'canny');
anyedge = ER | EG | EB;
figure, fig5=imshow(anyedge)
size(fig5)
fig = figure;
outfile = fullfile(outfolder, sprintf('%s-coba-%03d.jpg', basename, iFiles));
saveas(fig5, outfile);
% yang dihitung dimensinya yaitu citra hasil segmentasi
[n, r] = fboxcount(figure,'slope');
%Perhitungan dimensi
df = -diff(log(n))./diff(log(r));
%Menampilkan hasil dimensi
disp(['Df= ' num2str(mean(df(4:8)))]);
% % end
end
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Walter Roberson
am 13 Mär. 2021
you are passing in something that isn't an rgb image.
18 Kommentare
Walter Roberson
am 18 Mär. 2021
Store the following code in the file named box_the_names.m
image_folder = 'F:\kuliah\semester6\TA2\mencoba';
files = dir(fullfile(image_folder, '*.jpg'));
filenames = fullfile({files.folder}, {files.name});
filenames = char(filenames).';
filenames(end+1:ceil(size(filenames,1)/3)*3, :) = ' ';
filenames = rescale(double(filenames), 0, 1, 'InputMin', 32, 'InputMax', 127);
names_cmap = reshape(filenames, 3, []).';
[n, r] = fboxcount(names_cmap,'slope');
and use your existing fboxcount.
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