Filter löschen
Filter löschen

traversing a long matrix

2 Ansichten (letzte 30 Tage)
pammy
pammy am 9 Mai 2013
i've a matrix named A of size 2 x 16421
i want to compare one row with the other rows and whenever there is a match it spaecifies their index i mean which row number matches
A=[ 12 45
32 56
19 89
12 45
1 0
0 0
44 21
32 56
32 56
12 45
33 78
90 32
19 89 and so on....]
it starts with 12 45 and compare it with all other rows and shows there index value next it starts with 32 56 and compare it with other rows and when there is a match shows their index.
when i traverse it one by one it takes very long time can anybody tell me how can i do so?

Akzeptierte Antwort

John Doe
John Doe am 9 Mai 2013
Bearbeitet: John Doe am 9 Mai 2013
I think this should work
ind = find(A(:,1) == A(:,2));
- Rob

Weitere Antworten (1)

Kategorien

Mehr zu Matrix Indexing finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by