division of a single column matrix

i have a single column matrix A=0 0 0 1 1 1 1 0 0 0 0 2 2 2 2 0 0 0 0 1 1 1 now i have to divide this in to several matrices such whenever 0 changes to 1 or 2 i want a new matrix in this case A1= 1 1 1 1 0 0 0 0; A2=2 2 2 2 0 0 0 0 ;A3= 1 1 1 which are also single column matrices ............using for loop

1 Kommentar

Oleg Komarov
Oleg Komarov am 16 Mai 2011
See my double edited answer in the previous post.

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Antworten (1)

Andrei Bobrov
Andrei Bobrov am 16 Mai 2011

0 Stimmen

in this case
A = A(:);
I = cumsum([0;diff(A)]~=0 & (A == 1 | A == 2));
out = arrayfun(@(x)A(I==x),1:max(I),'un',0);
Dear bilhan! I think it is necessary to remove the question. See commentary by Oleg Komarov

4 Kommentare

Oleg Komarov
Oleg Komarov am 16 Mai 2011
This a duplicate post and the op asked a loop solution: http://www.mathworks.com/matlabcentral/answers/7497-dividing-a-column-matrix-based-on-the-no
Andrei Bobrov
Andrei Bobrov am 16 Mai 2011
Hi Oleg, i'm to blame, did not notice.
Oleg Komarov
Oleg Komarov am 16 Mai 2011
You can add your answer to the other post. Multiple interpretations are always useful.
Andrei Bobrov
Andrei Bobrov am 16 Mai 2011
well

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am 16 Mai 2011

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