Cholesky factorization on symbolic matrix

7 Ansichten (letzte 30 Tage)
Chien-Chia Huang
Chien-Chia Huang am 16 Mai 2011
Hi all,
I want to use Cholesky factorization on some symbolic matrices but I am still working with R2007b, quite an old version.
I met error message when I did it.
Is there any other way out to do this in R2007b?
--
I do have an authorized R2011a but the toolboxes are not included. (I have no idea why my school did not purchase the full version.)
So guess I cannot, for this time being, work with R2011a unless I know how to transfer all the toolboxes from my current version to the latest one.
Could anyone tell me how to do this? (Just copy all the files?)
Thanks in advance.

Akzeptierte Antwort

Kai Gehrs
Kai Gehrs am 17 Mai 2011
If you want to do the computation inside of MuPAD, you can use
n:= 4:
A:= matrix([[c.i.j $ i = 1..n] $ j = 1..n]):
linalg::factorCholesky(A,NoCheck)
The option 'NoCheck' means that it is not checked whether A is symmetric and positive definite.
  1 Kommentar
Chien-Chia Huang
Chien-Chia Huang am 17 Mai 2011
Thanks, Kai. But MuPad is contained in new Matlab version. I did not found it in my "antique" R2007b.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

Walter Roberson
Walter Roberson am 16 Mai 2011
Toolboxes cannot be transferred between versions.
  5 Kommentare
Chien-Chia Huang
Chien-Chia Huang am 17 Mai 2011
Thanks Walter. I did exactly what you say in your comment and got what I wanted.
Also to Andrei, I have tried and it works. But the answer is not as "pretty" as that in Maple. What should "C" be? what I input is C = [1 a b c;a 1 d e;b d 1 f;c e f 1].
Walter Roberson
Walter Roberson am 17 Mai 2011
I would suggest
maple('Chol := C->LinearAlgebra[LUDecomposition](Matrix(C,form=symmetric),method=Cholesky)':);
syms a b c d e f
C = [1 a b c;a 1 d e;b d 1 f;c e f 1];
maple('Chol', C);

Melden Sie sich an, um zu kommentieren.

Produkte

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by