I'm trying to work with integrals that are functions of one of their limits:
For example,
phi = @(x) quad(@(L) besseli(1, (1+L)/(1-L)), 0, x);
What I'm trying to do is evaluate phi over an array of values, like:
phi([1,2,3,4]); %ERROR
quad(@(L) besseli(1, (1+L)/(1-L)), 0, [1,2,3,4]); %ERROR
but these return errors. I could do this in a for loop, like:
nums=[1,2,3,4];
for(k=1:4)
phi_eval = phi(nums(k));
end
but I was wondering if there was a better way to do things. Is there a no-for-loops way of doing this?

 Akzeptierte Antwort

Shashank Prasanna
Shashank Prasanna am 29 Apr. 2013

0 Stimmen

Christopher, I can't run the loop as well. But phi([1,2,3,4]) will certainly not work because the vector is being passed to quad directly as limits which is wrong syntax for quad.
You can try the following:
arrayfun(phi,[1,2,3,4])

6 Kommentare

Great, thanks! If I had known about arrayfun, I probably would've done that from the beginning.
I also found another solution that involved u-substitution in the integral (which allowed the limits to be from 0 to 1 instead of 0 to L) and the quadv function:
nums = [1,2,3,4];
phi = quadv(@(L) besseli(1, (1+L.*nums)./(1-L.*nums)).*nums, 0, 1);
Note that both quad and quadv are deprecated. Use integral instead. If you want to integrate a vector-valued problem, use
integral(...,'ArrayValued',true)
Wenjuan
Wenjuan am 5 Dez. 2013
What if both limits are vectors as well? I don't think integral, quad or quadv can deal with this, but how to use arrayfun in this? Thanks.
Leo Simon
Leo Simon am 11 Feb. 2014
I too would like to specify vector valued integration limits. If anybody from mathworks is listening could you please respond? This should be really easy to implement I imagine, and hopefully will be in the next release?
Please go to my profile. Where it says "email", click on "contact Mike Hosea" and tell me about your use cases for array-valued limits. If we're talking generic array limits, where there is no a priori relationship between the different elements of the limits, then no gain in efficiency can be had over writing a loop. E.g.
Q = zeros(size(a));
for k = 1:numel(Q)
Q(k) = integral(f,a(k),b(k));
end
For scalar-valued integrations, that can also be accomplished efficiently with an application of arrayfun, e.g.
Qarray = @(a,b)arrayfun(@(ak,bk)integral(f,ak,bk),a,b);
Q = Qarray(a,b);
However, if we are talking about table-building, where the limits represent a grid, then efficiency improvements are possible. The latter use case might be accomplished by some other means, however, such as providing scalar limits and a list of output points for the integrals over partial regions.
it works with both array limits as well:
phi = matlabFunction(int(x^2,x,a,b));
arrayfun(phi,vec1,vec2)

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Hilfe-Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by