Hi all,
I am trying to plot four given values on matlab.
the values are
t = 0;
ta = 0.63;
tb = 0.71;
tc = 0.5;
Could anybody advice how can this been plotted on matlab?
It's been a long time I've used matlab, and I have lost the touch of the commands.
Thanks in advacne for those who oculd help.

5 Kommentare

Jos Jordan
Jos Jordan am 6 Feb. 2021
I don't understand - how would you like to plot them?
The scatter() function could work, but what variables are on the axes and how are they related to the variables you have given?
bagya vivekanandhan
bagya vivekanandhan am 6 Feb. 2021
Hi!
I am trying for basic line plot that i'm trying to plot. Assuming the suitable range on the x and y axis.
As an example : on both x and y axis : it's 0 : 0.1 : 1.
Jos Jordan
Jos Jordan am 6 Feb. 2021
So do you mean of an y/x graph, each point would have the value
t = [0, 0];
ta = [0.63, 0.63];
tb = [0.71, 0.71];
tc = [0.5, 0.5];
or am I misunderstanding the question?
bagya vivekanandhan
bagya vivekanandhan am 6 Feb. 2021
You have understood it right. That's how i wanted to plot. How can i process with that?
I'm sorry, I could've tried to explain it better.
Thanks.
Cris LaPierre
Cris LaPierre am 6 Feb. 2021
I strongly suggest you go through MATLAB Onramp. Ch 9 covers plotting.

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 Akzeptierte Antwort

Cris LaPierre
Cris LaPierre am 6 Feb. 2021
Bearbeitet: Cris LaPierre am 6 Feb. 2021

0 Stimmen

Based on what you've shared, I'd probably do the following.
t = 0;
ta = 0.63;
tb = 0.71;
tc = 0.5;
plot([t,ta,tb,tc])
Y values are the 4 values you have provided. Since no X values were provided, index number is used - the first y value is assigned the x value of 1, the 2nd gets and x value of 2, etc.

Weitere Antworten (1)

Jos Jordan
Jos Jordan am 6 Feb. 2021

0 Stimmen

Given that:
t = [0, 0];
ta = [0.63, 0.63];
tb = [0.71, 0.71];
tc = [0.5, 0.5];
you could then set
x = [0, 0.63, 0.71, 0.5];
x = y;
plot(x,y);
and then use the property inspector to play around until you make it look as you want to.

1 Kommentar

bagya vivekanandhan
bagya vivekanandhan am 6 Feb. 2021
Thanks a lot, That worked!
I'll go through the referred!

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