Filter löschen
Filter löschen

Simple Integration

1 Ansicht (letzte 30 Tage)
Bibha
Bibha am 13 Mai 2011
Hi there,
I am new to MATLAB and have a simple question regarding the integration.
I have two expressions:
syms c L;
first = int( exp(-(L-3)^2/2, c, Inf);
second = int (first * exp(-(c-5)^2/.5), -Inf, Inf);
It gives me the integral of the first expression however on the second it says "Explicit integral could not be found". Then I also tried with quad but no avail.
what should I do to evaluate the second integral?
Many Thanks.

Akzeptierte Antwort

Teja Muppirala
Teja Muppirala am 13 Mai 2011
QUADGK works better for integrals that go to infinity:
syms c L;
first = int( exp(-(L-3)^2/2), c, Inf);
second = matlabFunction (first * exp(-(c-5)^2/.5));
quadgk(second,-inf,inf)
  1 Kommentar
Bibha
Bibha am 13 Mai 2011
It worked!
Thanks! Thanks! Thanks and thanks.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

Ivan van der Kroon
Ivan van der Kroon am 13 Mai 2011
Bibha,
It get this answer for your third line (note also that on line two a right bracket is missing).
second =
infinity
/
| 2
| exp(-2.000000000 (c - 5) )
|
/
-infinity
1/2 1/2 1/2 1/2 1/2 1/2
(- 1/2 pi 2 erf(1/2 2 c - 3/2 2 ) + 1/2 pi 2 ) dc
I really do not think this integral can be evaluated explicitly. It is an error-function multiplied with a exponential function.
Ciao, Ivan
  1 Kommentar
Bibha
Bibha am 13 Mai 2011
I think, I agree with you that the integral can NOT be evaluated explicitly. For that reason, I tried QUAD but I could not get it worked.
Any help on QUAD?

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Mathematics finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by