I need help with Range equation and range error
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
University Student
am 2 Feb. 2021
Beantwortet: Walter Roberson
am 3 Feb. 2021
I have set up these values in matlab. I need help finding the jacobian matrix for the system. Can I just use the jacobian function provided by matlab?
I also need help with solving for the expected solution uncertainty (1-sigma.
This equation should solve for x and y correct? I need to solve for this as well.
Finally how can I put this solution in a monte carlo simulation?
a = [0 10 0 10];
b = [0 0 10 10];
r = [25 45 65 85];
range_error = 0.5
(r^2)=((x-a)^2) + ((y-b)^2));
0 Kommentare
Akzeptierte Antwort
Walter Roberson
am 3 Feb. 2021
syms a b x y r
eqn = (x-a)^2 + (y-b)^2 - r^2
J = jacobian(eqn, [x y])
syms tolp toln
assume(tolp > 0 & toln > 0)
range_error = 0.5
eqn1 = eqn + tolp - range_error^2
eqn2 = eqn - toln - range_error^2
J1 = jacobian(eqn1, [x y])
J2 = jacobian(eqn2, [x y])
What I did was transform
%sqrt((x-a)^2 + (y-b)^2) = r + delta, -range_error <= delta <= range_error
into equalities, giving a name to the difference between the ideal match and the actual match; split it into two parts, one with a positive difference and one with a negative difference, and require that the variable be positive. Like A > B means that A = B + delta where delta > 0. MATLAB is a lot more comfortable reasoning about equalities and then eliminating the branches that would violate the assume(), than it is trying to solve inequalities.
0 Kommentare
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Systems of Nonlinear Equations finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!