Reynolds number, FalsePosition getting multiple errors with no output
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
I am to create a function that uses FalsePosition (function shown below) to solve for f in the given equation. I think I'm missing some connections between my script and the function I'm trying to call.
Here is FalsePosition
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/497398/image.png)
This is my code:
function [root, fx, ea, iter] = falsepositionnew(y)
xl = 2500;
xu = 1000000;
es = 0.0000001;
maxit = 200;
Re = 10000:200000;
y = @(f, Re) 1/sqrt(f) - 4*log(Re*sqrt(f))+0.4; %equation given
for = i:numel(Re)
f(i) = falseposition(y,xl,xu,es,maxit);
end
0 Kommentare
Antworten (0)
Siehe auch
Kategorien
Mehr zu Statics and Dynamics finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!