Attempted to access b(0,:); index must be a positive integer or logical.

for k=1:14;
    [col,row]=size(b);
    prj=zeros(col,1);
    for i=1:col
        for j=1:row
            if b(i,j)==0
                prj(i)=prj(i)+1;
            end
        end
    end
    rup = 0;rdw = 0;
    for i = 1:col
        if prj(i)==0 && prj(i+1)>=1
            rup = i;
        end
        if prj(i)>=1 && prj(i+1)==0
            rdw = i+1;
            break
        end
    end
    range = rdw-rup;
    ab = ones(range,row);
    for i= rup:rdw
        ab(i-rup+1,:) = b(i,:);
        b(i,:)=1;
    end
    figure;imshow(ab);
    k=k+1;
end

I have some problems with the above code and I keep getting the "attempt to access" error.

The size of matrix b is [3508 2480].

Can anybody shed some like as to fix it?

I get the following error:

Attempted to access prj(3509); index out of bounds
because numel(prj)=3508.

Error in main (line 67)
        if prj(i)==0 && prj(i+1)>=1

Answer 1

[Walter Roberson]

You start with rup = 0. You then have a loop that conditionally assigns a different value to rup. You then loop "i" starting from rup. But suppose the conditions of the conditional assignment were never true: then rup would still be 0, and you would be looping starting from 0.

Answer 2

[Andy]

Thank you for your explanation. It seems really complicated to understand. Are there anything that I can change to make it work? Like plus 1 somewhere? Thanks!

[Walter Roberson]

You need to decide what you want to do if your "for i = 1:col" loop does not find any matches.