Matrix function -- problem with the defi

4 Ansichten (letzte 30 Tage)
Mikl Nik
Mikl Nik am 12 Jan. 2021
Beantwortet: 埃博拉酱 am 24 Jan. 2025
Hi!
I wrote this code where Y is a cell array (actually is a matrix [y1; y2; y3] and F is a matrix that I would like to be like the function of Y -- I mean if Y = [y1; y2; y3] -> F(Y) = [1; y3; f(y1, y2, y3)] where f - another function.
How can I realize this in Matlab? Unfortunely this code does not work in an appropriate way. ;(
Thanks!
Y = @(y1, y2, y3) {@(y1) y1; @(y2) y2; @(y3) y3};
F = @(Y) [1; Y(3); f(Y(1), Y(2), Y(3))]
  1 Kommentar
Aditya
Aditya am 24 Jan. 2025
Hi Mikl,
To solve your problem with defining the function F(Y), you can use MATLAB's function handles and anonymous functions. These resources will guide you on how to define and work with them:
I hope this helps!

Melden Sie sich an, um zu kommentieren.

Antworten (1)

埃博拉酱
埃博拉酱 am 24 Jan. 2025
function Y=F(Y,f)
y3=Y(3,:);
Y(2:3,:)=[y3;f(Y(1,:),Y(2,:),y3)];
Y(1,:)=1;
end

Kategorien

Mehr zu Mathematics finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by