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What does this print out?
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a = 3;
b = a;
a = 1;
while (b<a)
b = b + 1;
disp(b)
end
I thought this would create an infinite loop is that correct?
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Paulo Silva
am 9 Mai 2011
it never prints, the condition is false
do this before the loop
b<a %replacing b and a by their first values you get 3<1
answer is 0 because the condition is false thus the loop never begins
3 Kommentare
Paulo Silva
am 9 Mai 2011
the condition is tested in the while line, if true the while begins, does what's inside it and in the end it tests again the condition, if false the code inside the while loop is "ignored"
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