Why my vars become to NaN?
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Dear Coders,
I have been testing the following code section by section and at first glance it worked properly, but when I have tested the code to plot only one curve per month, so that twelve curves, the vars ME2 and ME3 accumulate NaN values. Why this problem arises?
To add more information, Matlab return me this message
"REE_perfiles2020
Array indices must be positive integers or logical values.
Error in REE_perfiles2020 (line 174)
plot([ME(1i)])"
REE=xlsread('REE_perfiles2020.xlsx',1,'a3:h8786');
REE(744); %%%%V
NDias=REE(:,1); %%%%%
%%%%
aP=REE(:,4); %
ai=reshape(aP,[24, 366]); %%%%%
%
for NDias=1:length(NDias)
%
if NDias==1
[row1, col]=find(NDias==1);
dEne=length(row1)/24; %%%
E=ai(:,(1:31));
ME=mean(E,2);
elseif NDias==2
[row2, col]=find(NDias==2);
dFeb=length(row2)/24;
ld2=row2/24;
logFeb=max(ld2)-dFeb;
E2=ai(:,((max(ld2)-dFeb)+1:max(ld2)));
ME2=mean(E2,2);
elseif NDias==3
[row3, col]=find(NDias==3);
dMar=length(row3)/24;
ld3=row3/24;
logMar=max(ld3)-dMar;
E3=ai(:,((round(ld3)-dMar)+1:max(ld3)));
ME3=mean(E3,2);
elseif NDias==4
[row4, col]=find(NDias==4);
dAbr=length(row4)/24;
ld4=row4/24;
logAbr=max(ld4)-dAbr;
E4=ai(:,(round(logAbr):max(ld4)));
ME4=mean(E4,2);
elseif NDias==5
[row5, col]=find(NDias==5);
dMay=length(row5)/24;
ld5=row5/24;
logMay=max(ld5)-dMay;
E5=ai(:,((round(ld5)-dMay)+1:max(ld5)));
ME5=mean(E5,2);
elseif NDias==6
[row6, col]=find(NDias==6);
dJun=length(row6)/24;
ld6=row6/24;
logJun=max(ld6)-dJun;
E6=ai(:,((round(ld6)-dJun)+1:max(ld6)));
ME6=mean(E6,2);
elseif NDias==7
[row7, col]=find(NDias==7);
dJul=length(row7)/24;
ld7=row7/24;
logJul=max(ld7)-dJul;
E7=ai(:,((round(ld7)-dJul)+1:max(ld7)));
ME7=mean(E7,2);
elseif NDias==8
[row8, col]=find(NDias==8);
dAgo=length(row8)/24;
ld8=row8/24;
logAgo=max(ld8)-dAgo;
E8=ai(:,((round(ld8)-dAgo)+1:max(ld8)));
ME8=mean(E8,2);
elseif NDias==9
[row9, col]=find(NDias==9);
dSep=length(row9)/24;
ld9=row9/24;
logSep=max(ld9)-dSep;
E9=ai(:,((round(ld9)-dSep)+1:max(ld9)));
ME9=mean(E9,2);
elseif NDias==10
[row10, col]=find(NDias==10);
dOct=round(length(row10)/24);
ld10=row10/24;
logOct=max(ld10)-dOct;
E10=ai(:,(((round(logOct)-dOct)+1:max(ld10))));
ME10=mean(E10,2);
elseif NDias==11
[row11, col]=find(NDias==11);
dNov=length(row11)/24;
ld11=row11/24;
logNov=max(ld11)-dNov;
E11=ai(:,(((round(logNov)-dNov)+1:max(ld11))));
ME11=mean(E11,2);
else
[row12, col]=find(NDias==12); %%%l
dDic=length(row12)/24; %%%%
ld=row12/24;
logDic=max(ld)-dDic;
E12=ai(:,((max(ld)-dDic)+1:max(ld)));
ME12=mean(E12,2);
end
plot(ME(1i))
hold on
end
0 Kommentare
Antworten (1)
KALYAN ACHARJYA
am 18 Dez. 2020
Bearbeitet: KALYAN ACHARJYA
am 18 Dez. 2020
Here
plot(ME(1i))
M(1i) what does it means? 1i is a complex number for MATLAB
>> 1i
ans =
0.0000 + 1.0000i
MATLAB allows positive integer indexing only. More. Before plot ME in each iteration, ensure that ME return as a vector. Note: There is no ME variable in elseif condition.It seems that the code needs some modification.
1 Kommentar
Siehe auch
Kategorien
Mehr zu Resizing and Reshaping Matrices finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!