how to plot a symbolic equation with 4 variables?

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Alex
Alex am 1 Apr. 2013
Does anyone know how to plot a symbolic equation containing 4 variables? u=f(x,y,z) using colour as the fourth dimension for u?
Thanks a lot!

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Walter Roberson
Walter Roberson am 1 Apr. 2013
Assuming that f is a symbolic expression in x, y, z, then:
ufun = matlabFunction(f, 'vars', {'x', 'y', 'z'});
xrange = linspace(-10, 10, 50); %for example
yrange = linspace(-pi, 3*pi/2, 50); %for example
zrange = linspace(1, 2, 57); %for example
[X, Y, Z] = ndgrid(xrange, yrange, zrange);
u = ufun(X, Y, Z);
pointsize = 10; %adjust as needed
scatter3(X, Y, Z, pointsize, u);
colormap(copper(256)); %choose appropriate colormap
  2 Kommentare
Alex
Alex am 1 Apr. 2013
Bearbeitet: Walter Roberson am 1 Apr. 2013
thanks for your helping hand, thanks to your reply I managed to figure out how to work with in N-D using ndgrid but I have one error puzzling me, can you help here?
[X, Y, Z] = ndgrid(1:200, 1:200, 1:200);
then I find U=...(omitted due to complexity)
scatter3(X,Y,Z,10,U)
and here the problem
Error using scatter3 (line 68)
X, Y and Z must be vectors of the same length.
it is strange because they were all created of equal length?
Walter Roberson
Walter Roberson am 1 Apr. 2013
scatter3(X(:), Y(:), Z(:), 10, U(:))
Warning: this is pretty slow for 200 x 200 x 200! Expect slowdowns to start once you get bigger than about 21 x 21 x 21. On my system, 50 x 50 x 50 is still peppy "enough" to draw originally, but rotating it is becoming clumsy. 200 x 200 x 200 took on the order of a minute or more to draw -- even just closing the figure took a good 30 seconds.

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