Indefinite Integral with Matlab

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Jeena am 30 Mär. 2013
Kommentiert: Walter Roberson am 4 Jun. 2018
Hi all,
I have a question about using indefinite integral in Matlab with out using symbolic toolbox. I have to find the integral for the following function
y@(x) = x + 2*sin(x) ;
I know how to do this with a symbolic variable using the 'int' function. But is there a way to do the indefinite integral when I defined the function by an anonymous function handle ? I was able to find the definite integral of the function using either 'integral' or by using 'quad'. But these functions cannot be used when I just need to integrate it indefinitely with out a bounded limit.
Can some help me to find a solution ?

Antworten (2)

Walter Roberson
Walter Roberson am 30 Mär. 2013
syms x
yx = y(x); %where y is the function handle
  2 Kommentare
Jeena am 1 Apr. 2013
Thanks for the answer, but still it uses a symbolic toolbox for the computation, right ???
I need to perform this computation without symbolic toolbox (or without any additional Matlab toolbox functions)...
Any suggestions ??
Walter Roberson
Walter Roberson am 1 Apr. 2013
Then you would have to convert the function to a string and analyze the string in order to do the integration, with it being quite possible that there is no known analytic solution for the indefinite integral. Your library of integration tools would have to be quite large, and yet you would be be easily thwarted by someone providing (for example)
@(x) cos(sin(x))
It is not possible to do indefinite integration numerically -- only by analysis of the known properties of the named functions.

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Pawan Kumar
Pawan Kumar am 4 Jun. 2018
i have attached a file with a function. How can write this function in matlab? Thanking you
  1 Kommentar
Walter Roberson
Walter Roberson am 4 Jun. 2018
The solution depends on whether k is positive, 0, or negative, and on the relative values of qs and 2*k . In some combinations of circumstances it is undefined. MATLAB is able to resolve some of the combinations if you add appropriate assumptions to the variables, but it is not able to tell you the full conditional resolution under other assumptions.

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