Help on for loop
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
I have an R vector and a U vector. The R vector contains mostly zeros but has a couple of values. The U vector is a shorter length than the R vector and contains no zeros. I want to make a U_final vector which has the values of the U vector at the same locations where the R vector values are non-zero. My attempted code is below. It iterates through fine, but the end result is the last value in U in all locations where R is non-zero rather than all values of U in the appropriate non-zero locations of R. I'm using U = [0.0137;0.0081] and R = [0;0;0;72;0;90]. I'd like the output to be U_final = [0;0;0;0.0137;0;0.0081]
for i = 1:length(R)
for j = 1:length(U)
if R(i,1) ~= 0
U_final(i,1) = U(j,1)
else U_final(i,1) == 0
end
end
end
1 Kommentar
Walter Roberson
am 12 Mär. 2013
Note that U_final(i,1) == 0 is a comparison statement, not an assignment.
Akzeptierte Antwort
Teja Muppirala
am 12 Mär. 2013
No need to iterate. MATLAB makes this simple with logical indexing.
U = [0.0137;0.0081];
R = [0;0;0;72;0;90];
U_final = R;
U_final(R~=0) = U
But the number of nonzeros in R needs to be equal to the length of U.
Weitere Antworten (1)
Youssef Khmou
am 12 Mär. 2013
Bearbeitet: Youssef Khmou
am 12 Mär. 2013
hi try this , BUT the number of non zeros in R must be the same as the length of U:
R=zeros(100,1);
R(2:4:55)=rand; % R contains some values ( 14 elements !)
U=rand(14,1); % U is Shorter than R and contains non zeros vals
index=find(R~=0); %locations where R has non zeros .
U_final=zeros(size(R)); % this is optional
U_final(index)=U;
0 Kommentare
Siehe auch
Kategorien
Mehr zu Logical finden Sie in Help Center und File Exchange
Produkte
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!