I'm keep having an error 'Not enough input arguments' for this code

function [y] = DivisibleTest(M)
for m = 1 : length(M)
    if mod(M(m),2)==0
        y = ["%d is divisible by 2",m,num2str(M)];
       
    elseif mod(M(m),3)==0
       y = ["%d is divisible by 3",m,num2str(M)];
        
    elseif  mod(M(m),2)==0 && mod(M(m),3)==0
        y = ["%d is divisible by 2 AND 3",m,num2str(M)];
        
    else 
       y = ["%d is NOT divisible by 2 or 3",m,num2str(M)];
        
    end
end
end

Answer 1

[KSSV]

It looks like you have opened the function and run the code by pressing F5 key or run button in the editor. This is not the way to call a function. You need to call the function either in the command window or in the script with proper input values.

Call the function in the command window s shwon below.

M = 10 ;  % your input 
y = DivisibleTest(M) ; 
y

[Muhammed Berat Eyigün]

Yes, thank you very much body. Actually it looks like I have much to learn in Matlab :) Thanks again, god bless you.

Answer 2

[Geoff Hayes]

Muhammed - from the function signature

function [y] = DivisibleTest(M)

when calling this function, you need to provide an input parameter for M. I suspect that you are either running this code from the (MATLAB) File Editor, or are calling this function from the command line like

>> DivisibleTest

You need to call this function with an input like

>> DivisibleTest(42)  % or whatever input you wish

[Muhammed Berat Eyigün]

Thank you too maan. Appreciate it :)

Answer 3

[Steven Lord]

Others have commented on the fact that you need to call your function with an input argument. I want to point out a different problem that you have. One of your lines of code is unreachable. When you have code that looks like:

if condition1
    doA
elseif condition2
    doB
elseif condition3
    doC
else
    doD
end

exactly one of doA, doB, doC, and doD will execute. Even if something that satisfies condition 3 also satisfies condition 1, doA and doC will not both execute. If anything that satisfies condition 3 also satisfies condition 1 but not the reverse, you should check for condition 3 first.

if x < 3
    disp('x is less than 3')
elseif x < 5
    disp('x is less than 5')
elseif x < 10
    disp('x is less than 10')
else
    disp('x is greater than or equal to 10')
end

Try defining x to have various values between say 1 and 20 and run that example then do the same for the following example:

if x < 10
    disp('x is less than 10')
elseif x < 5
    disp('x is less than 5')
elseif x < 3
    disp('x is less than 3')
else
    disp('x is greater than or equal to 10')
end

[Muhammed Berat Eyigün]

Yes, you were right. I fixed that one but still have one. When I execute the function it just goes to the value that at the end of the M and take that value into consider and makes the calculation for that value. I have just 1 display. But I need all the values, what should I do?

[Muhammed Berat Eyigün]

function [y] = DivisibleTest(M)
for m = 1 : length(M)
    if  mod(M(m),2)==0 && mod(M(m),3)==0
        y = fprintf("%d is divisible by 2 AND 3\n",M(m));
    elseif mod(M(m),3)==0
       y = fprintf("%d is divisible by 3\n",M(m));
        
    elseif  mod(M(m),2)==0
       y = fprintf("%d is divisible by 2\n",M(m));
    else 
       y = fprintf("%d is NOT divisible by 2 AND 3\n",M(m));
        
    end
end
end

This is the last version of the code, fixed all the previous problems, now I have just last one :) Code makes the everything I want but at the end gives y value equals some value I dont understand. For example;

M=[12,45,78,96,10,3,8];
>> y=DivisibleTest(M)
12 is divisible by 2 AND 3
45 is divisible by 3
78 is divisible by 2 AND 3
96 is divisible by 2 AND 3
10 is divisible by 2
3 is divisible by 3
8 is divisible by 2

y =

    20