Hi,
I have a structure of size S=18x112x50. Here 18=different patients, [112 is (1:37)=class 1 and 38:112=class 0] and 50 = no. of iterations. Now i need to perform Leave one out method to find the accuracy of the feature. For eg: Train1=s1(1:17,:,:),Test1=(18,:,:), run classification algorithm (anything like SVM, LDA etc)get the accuracy, and in second iteration Train2=s1(2:18,:,:),Test2=(1,:,:) and so on as leave one out.

Antworten (1)

Shashank Prasanna
Shashank Prasanna am 26 Feb. 2013

0 Stimmen

Sunil, if you have the Statistics Toolbox you can use 'crossval' to perform leave one out cross validation:
You can set 'leaveout' to be 1. The above link has examples on how to use the function.

4 Kommentare

Sunil
Sunil am 26 Feb. 2013
Hi, I am new to this classification problem. Any demo code for LOO on an example data (of size mxnxp) would be helpful.
Shashank Prasanna
Shashank Prasanna am 26 Feb. 2013
I am afraid I don't understand what you mean by LOO, but as I already mentioned there are examples on how to cross validate classification right at the bottom of the page. You will have to scroll all the way down.
sweet dm
sweet dm am 19 Nov. 2017
hi please tell me when we have small data of 60 instance can we do the loo as classification without using test part ??
Bernhard Suhm
Bernhard Suhm am 22 Apr. 2018
You can, but neither the model nor its accuracy estimate will be very reliable with this small a dataset.

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