Loop with row and column difference (multiplication)

2 Ansichten (letzte 30 Tage)
Jacqueline Rigatto
Jacqueline Rigatto am 10 Nov. 2020
I would like to know how I do a loop multiplying Q1 with O3 (result in Q3). Then multiply Q3 with O4 and so on for each column.
I tried to explain with other software to facilitate understanding. Thank you for your help.
  3 Kommentare
David Hill
David Hill am 10 Nov. 2020
Did you look at my answer? First load your file and look at the data to see how it was loaded (how it is named). It would help if you attached your data file.
load('yourfile');

Melden Sie sich an, um zu kommentieren.

Antworten (2)

Cris LaPierre
Cris LaPierre am 10 Nov. 2020
Assuming you meant to include a Q2, I'd do this using cumprod instead of a for loop.

David Hill
David Hill am 10 Nov. 2020
Bearbeitet: David Hill am 10 Nov. 2020
I assume your arrays when imported will start at 1. Looks like you just want cumprod() of O times initial Q.
Q(2:end)=Q(1)*cumprod(O);
  6 Kommentare
Jacqueline Rigatto
Jacqueline Rigatto am 11 Nov. 2020
I managed to do it using the code:
clear all; clc; close all
alpha=0.008;
gamma=3.3;
g=9.8;
delta_1=0.07;
delta_2=0.09; % if f>fp
Tp=[2 8 16];
freq_p=1./Tp;
i_freq=1:69;
f1=0.03093;
c=1.1;
for i = 1:length(i_freq)
fi=f1.*c.^(i_freq-1);
end
freq_fi=fi;
nrows = length(freq_fi);
ncols = length(freq_p);
E = ones(nrows,ncols);
fc = 0.4054; % [rad/s]
for i = 1:nrows
for j = 1:ncols
f = freq_fi(i);
fp = freq_p(j);
if f<fc
if f<=fp
E(i,j) = (alpha*(g^2)*((2*pi)^(-4))*(f^(-5)))*exp((-5/4)*((f/fp)^(-4)))*gamma*exp((-1/2)*((f-fp)/(delta_1*fp))^2);
else
E(i,j) = (alpha*(g^2)*((2*pi)^(-4))*(f^(-5)))*exp((-5/4)*((f/fp)^(-4)))*gamma*exp((-1/2)*((f-fp)/(delta_2*fp))^2);
end
elseif f>fc
if f<=fp
E(i,j) = (fc/f)^5*(alpha*(g^2)*((2*pi)^(-4))*(f^(-5)))*exp((-5/4)*((f/fp)^(-4)))*gamma*exp((-1/2)*((f-fp)/(delta_1*fp))^2);
else
E(i,j) = (fc/f)^5*(alpha*(g^2)*((2*pi)^(-4))*(f^(-5)))*exp((-5/4)*((f/fp)^(-4)))*gamma*exp((-1/2)*((f-fp)/(delta_2*fp))^2);
end
else
E(i,j)=0;
end
end
end
E;
%%% Dir(teta)
i_teta=1:36;
teta_i=10.*i_teta;
teta_i_cos=cos(2*teta_i);
for i = 1:length(teta_i_cos)
if teta_i_cos>0
dir_teta=0;
else
dir_teta= (2/pi())*(1/2)*(1+teta_i_cos);%cos^2(x) = (1+cos2x)/2
end
end
dir_teta;
f_teta=teta_i;
%%%%%%%%%%%%% My problem below %%%%%%%%%%%%%%%%%%%%
%%% T=2s
T2=E(:,1);
T2=T2';
aux1=cumprod(dir_teta');
aux2=repmat(aux1,1,69);
aux3=aux2.*T2;
Thank you for your help David Hill
Jacqueline Rigatto
Jacqueline Rigatto am 11 Nov. 2020
And I'm sorry for the confusion I made.

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Matrix Indexing finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by