x(t)=log(8)[t+Π(t)], t=[1e-4, 10]

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milton
milton am 8 Nov. 2020
Kommentiert: milton am 25 Nov. 2020
I want to restore the above signal on a variable and plot it in the time gap that it is given. Any help please?

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Rohit Pappu
Rohit Pappu am 25 Nov. 2020
% Vector to define t
t = [1e-4:0.001:10];
% product of all time instances
prod_t = prod(t);
% x(t)
x = log(8)*(t+prod_t);
% Plot t on x axis and x(t) on y axis
plot(t,x);
  1 Kommentar
milton
milton am 25 Nov. 2020
Thank you! It works perfectly!

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